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3 votes
If f(x) = x^2/x+3, find f(x+h)

2 Answers

1 vote

Answer:

Explanation:

You just need to replace all the x's in the equation with (x+h).

So (x+h)^2/(x+h)+3.

I can't tell from the original, but if it is ((x+h)^2) / ((x+h)+3), (over the complete thing) then it can't be simplified and that is the answer.

But if it is ((x+h)^2)/(x+h) + 3, then you can cancel one of the (x+h)'s on the top and get (x+h) + 3 overall.

User Daniel Fanjul
by
6.3k points
5 votes

Answer:


f(x+h)=(x^2+2xh+h^2)/(x+h+3) is the answer

given the function
f(x)=(x^2)/(x+3).

Explanation:


f(x)=(x^2)/(x+3) is the given function.

I'm going to do some examples of plugging in because that is what this problem is asking you to do.

Example 1: What is f(2)?

f(2) means we are going to replace x with 2 in the thing we called f:


f(2)=(2^2)/(2+3)


f(2)=(4)/(5)

Example 2: What is f(-2)?

f(-2) means we are going to replace x with -2 in the thing we called f. Before we do this I just wanted to tell you something here about negative numbers or expressions. When plugging in either of these, use ( ) around the number you are plugging in. So I should re-say my first line here.

f(-2) means we are going to replace x with (-2) in the thing we called f:


f(-2)=((-2)^2)/((-2)+3)


f(-2)=(4)/(1)


f(-2)=4.

Example 3: What is f(cat+tuna)?

f(cat+tuna) means we are going to replace x with (cat+tuna) in the thing we called f:


f(\text{cat+tuna})=\frac{(\text{cat+tuna})^2}{(\text{cat+tuna})+3}


f(\text{cat+tuna})=\frac{(\text{cat+tuna})^2}{\text{cat+tuna}+3}

To expand the top, we are going to use this formula for squaring a sum:


(u+v)^2=u^2+2uv+v^2.


f(\text{cat+tuna})=\frac{(\text{cat})^2+2\cdot \text{cat} \cdot \text{tuna}+(\text{tuna})^2}{\text{cat+tuna}+3}

Ok let's move on to the true problem:

f(x+h) means to replace x with (x+h) in the thing we called f:


f(x+h)=((x+h)^2)/((x+h)+3)

This is really the same problem we had above except without the cat and the tuna but with x and h respectively instead.


f(x+h)=(x^2+2xh+h^2)/(x+h+3)

User Alexandre Legent
by
6.2k points
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