Question

What are the zeros of f(x) = x2 - 12x + 36?

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A. x= -6 and x = 6
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B. x=-6 only
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c. x= 6 only
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D. x= -4 and x = 9

Answer 1

c. x = 6 only

Explanation:

In order to calculate the zeros of f(x), we need to set it equal to zero and find the corresponding values of x.

`x^(2)-12x+36=0`

Using the midterm breaking, we can split -12x into two such terms whose sum will be -12x and product will be 36x². These two terms are -6x and -6x

So, the above expression can be written as:

`x^2-6x-6x+36=0\\\\ x(x-6)-6(x-6)=0\\\\ (x-6)(x-6)=0\\\\ (x-6)^(2)=0\\\\ x-6=0\\\\ x=6`

This means, the zero of f(x) occurs at x = 6 only.