Question

Which of the following is a polynomial function in standard form with zeros at –6, 2, and 5?

f(x) = (x + 6)(x – 2)(x – 5)

f(x) = x3 + x2 – 32x – 60

f(x) = x3 – x2 – 32x + 60

f(x) = (x – 6)(x + 2)(x + 5)

Answer 1

option A is correct

Explanation:

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Answer 2

Option C is correct.

Explanation:

We need to find the polynomial function in standard form with zeros at –6, 2, and 5

If a is a zero of polynomial then x-a is the factor of polynomial

So, (x+6)(x-2)(x-5) are factors of polynomial.

Multiplying these factors to find the standard polynomial function

(x+6)(x-2)(x-5)

We need to solve this:

(x+6)(x^2-5x-2x+10)

(x+6)(x^2-7x+10)

x^3-7x^2+10x+6x^2-42x+60

x^3-7x^2+6x^2+10x-42x+60

x^3-x^2-32x+60

So, Option C f(x) = x3 – x2 – 32x + 60 is correct.