Solution:
Total no. of incoming calls, n = 20
Probability of incoming calls with fax messages, p = 20% = 0.20
q = (1 - p) = 0.80
(a) Now, let 'r' be the no. of incoming calls with fax messages, then by Binomial distribution of probability mass function:
P(X = r) =
(1)
P(X ≤ 7) =
![_(0)^(20)\textrm{C} (0.20)^(0)(0.80)^(20) +...... + _(7)^(20)\textrm{C} (0.20)^(7)(0.80)^(13)](https://img.qammunity.org/2020/formulas/english/college/bhllileey6pvw5fqpc6qr70f904rallsbr.png)
P(X ≤ 7) = 0.0115 +........+ 0.0545
Total no. of incoming calls, n = 20
Probability of incoming calls with fax messages, p = 20% = 0.20
q = (1 - p) = 0.80
(a) Now, let 'r' be the no. of incoming calls with fax messages, then by Binomial distribution of probability mass function:
P(X = r) =
(1)
P(X ≤ 7) =
P(X ≤ 7) = 0.0115 + 0.0545
P(X ≤ 7) = 0.9689
probability that atmost 7 of the calls are with fax is 0.9689