Question

A cat started at a distance of 5.4 m away from your front door and began walking directly away from it. 2 minutes later, the cat was 9.3 m from your door. if d is the distance of the cat from the door, what is (delta)d

A. 3.9
B. 9.3
C. 5.4
D. 2

Answer 1

Answer: A. 3.9 m

Step-by-step explanation:

The variation in distance
`\Delta d` is given by:

`\Delta d=d_(f)-d_(o)` (1)

Where
`d_(f)=9.3m` is the final distance of the cat from the door and
`d_(o)=5.4m` is the initial distance of the cat from the door.

Solving (1) with the known values:

`\Delta d=9.3m-5.4m=3.9m` (2)

Hence:

`\Delta d=3.9m`