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6 votes
Question 2
Find three consecutive odd integers whose sum is 99.

2 Answers

7 votes

Answer:15+84

35+64

79+20

Explanation:

User Ghassen Hamrouni
by
4.6k points
5 votes

Answer:

31, 33, 35

Explanation:

Let 2n+1 be the first odd number. What will the next one be? Add two:

Let 2n+3 be the next odd number. Again, what is the next one? Add two:

Let 2n+5 be the third odd number.

The sum of those three numbers must be 99. You don't have to have the parenthesis here, but I think they help clarify where everything comes from.

(2n+1) + (2n+3) + (2n+5) = 99

Add like terms, and solve for n:

6n + 9 = 99

6n = 90

n = 15

The three odd numbers we want are:

2(15)+1 = 31

2(15)+3 = 33

2(15)+5 = 35

Double check: 31+33+35 = 99?

User Helam
by
5.2k points