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A wheel 1.90 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 4.40 rad/s2. The wheel starts at rest at t = 0, and the radius vector of a certain point P on the rim makes an angle of 57.3° with the horizontal at this time. At t = 2.00 s, find the following. (a) the angular speed of the wheel

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Answer:

(a): The angular speed of the wheel is ω= 8.8 rad/s

Step-by-step explanation:

α= 4.4 rad/s²

t= 2 s

ω= α * t

ω= 8.8 rad/s

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