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If an object is dropped from a tall building and it hits the ground 3.0 s later, what is the velocity of the object when it hits the ground? (Remember that the velocity is downward)

V= _____ m/s

User Seraf
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4.8k points

2 Answers

3 votes

Answer:

-29.4 m/s

Step-by-step explanation:

User Curiousdork
by
5.0k points
2 votes

Answer:

-29.4 m/s

Step-by-step explanation:

Initial velocity is 0 m/s.

Acceleration is -9.8 m/s².

Time is 3.0 s.

v = at + v₀

v = (-9.8)(3.0) + 0

v = -29.4 m/s

User GhostJago
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4.8k points