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If p(x) = x2 - 1 and (x)= 5(x-1), which expression is equivalent to (0-2)(x)? 5(x - 1) – x2 - 1 (5x - 1) – (x2 - 1) (x2 - 1) – 5(x - 1) (x2 - 1) – 5x-1
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If p(x) = x2 - 1 and (x)= 5(x-1), which expression is equivalent to (0-2)(x)?

5(x - 1) – x2 - 1
(5x - 1) – (x2 - 1)
(x2 - 1) – 5(x - 1)
(x2 - 1) – 5x-1

User Berbie
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1 Answer

3 votes

Answer:

The first one

Explanation:

User Lrn
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