Answer:
0.647 nC
Step-by-step explanation:
The force experienced by a charge due to the presence of an electric field is given by
![F=qE](https://img.qammunity.org/2020/formulas/physics/high-school/brnfke1f9vkg4w0916oax03k6im4kc77bn.png)
where
q is the charge
E is the magnitude of the electric field
In this problem, each antenna is modelled as it was a single point charge, experiencing a force of
![F=5.50\mu N = 5.50\cdot 10^(-6) N](https://img.qammunity.org/2020/formulas/physics/college/ydnfuyhwdhx0c57l89b1zldzt07pwgetuh.png)
Therefore, if the electric field magnitude is
![E=8.50 kN/C = 8500 N/C](https://img.qammunity.org/2020/formulas/physics/college/knth2mtaqu5qgsuicgw6cvspoaf8dtj0hb.png)
Then the charge on each antenna would be
![q=(F)/(E)=(5.50\cdot 10^(-6) N)/(8500 N/C)=6.47\cdot 10^(-10) C = 0.647 nC](https://img.qammunity.org/2020/formulas/physics/college/5v8duvpbh6dc9o1nj0x8ey6tqa2lw06htk.png)