Question

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K

Answer 1

28.2 kPa on edge uwu

Step-by-step explanation:

Answer 2

• 0.0443 atm

Step-by-step explanation:

1) Data:

a) n = 0.540 mol

b) V = 35.5 liter

c) T = 223 K

2) Formula:

• Ideal gas equation: PV = nRT

Where,

• P = pressure
• V = volume
• n = number of moles
• T = absolute temperature (kelvin scale)
• R = universal gas constant = 0.08203 atm-liter/K-mol

3) Calculations:

• Solve for P

PV = nRT ⇒ P = nRT/V

• Substitute and compute:

P = 0.540 mol × 0.08206 atm-liter/K-mol × 223 K / 35.5 liter

P = 0.0443 atm (you must use 3 significant figures).