Question

If A= (-1,3) and B=(11,-8) what is the length of ab

Answer 1

16.3 units ( to 1 dec. place )

Explanation:

Using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(- 1, 3) and (x₂, y₂ ) = B(11, - 8)

AB =
`√((11+1)^2+(-8-3)^2)`

=
`√(12^2+(-11)^2)`

=
`√(144+121)`

=
`√(265)` ≈ 16.3 ( to 1 dec. place )