Question

A bouncy ball is dropped such that the height of its first bounce is 6.25 feet and each

successive bounce is 80% of the previous bounce's height. What would be the height

of the 11th bounce of the ball?

Answer 1

Answer: 0.7

Explanation:

Answer 2

0.67 feet

Explanation:

This question can be interpreted as find the 11th term of a geometry progression where a = 6.25 and r = 80%

So, we have:

`T_n = ar^(n-1)`

In this case:

`r - 80\% = 0.8`

`n = 11`

So, we have:

`T_(11) = 6.25 * 0.8^(11-1)`

`T_(11) = 6.25 * 0.8^(10)`

`T_(11) = 6.25 * 0.1073741824`

`T_(11) = 0.67ft`

Hence, the height of rebound at the 11th time is approximately 0.67