Question

-(2x-4)=6x+8 solve for x

Answer 1

Answer:
`x=\Large\boxed{-(1)/(2) }`

Explanation:

Given equation

`-(2x-4)=6x+8`

Expand the parenthesis

`-2x+4=6x+8`

Subtract 6x on both sides

`-2x+4-6x=6x+8-6x`

`-8x+4=8`

Subtract 4 on both sides

`-8x+4-4=8-4`

`-8x=4`

Divide -8 on both sides

`-8x/-8=4/-8`

`x=\Large\boxed{-(1)/(2) }`

Hope this helps!! :)

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Answer 2

`\sf x = (-1)/(2)`

Explanation:

To solve for 'x', isolate x.

-(2x - 4 )= 6x + 8

Multiply each term of LHS by (-1),

-2x + 4 = 6x + 8

Subtract 4 from both sides,

-2x = 6x + 8 - 4 {Subtraction property of equality}

-2x = 6x + 4

Subtract '6x' from both sides,

-2x - 6x = 4 {Subtraction property of equality}

-8x = 4

Divide both sides by (-8), {Division property of equality}

`\sf x = (4)/(-8)\\\\ x = (-1)/(2)`