Answer:
Part A)
![x=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iytjkob8c453cdntkigo6vyjyk3yzlat9o.png)
Part B) ∠3=29°
Part C) ∠1=29°
Part D) ∠2=151°
Explanation:
Part A) If ∠3=5x-1 and ∠5=3x+11, then x=?
we know that
∠3=∠5 ----> by alternate interior angles
so
substitute and solve for x
![5x-1=3x+11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xflr7fgbbk9rfbqmgwbmqh8o0xulsbvmnd.png)
![5x-3x=11+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fcfe77go2drflv0aroym3vnvlte3losd0d.png)
![2x=12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/irzp2l0haqekqzsz4lb8n1sm7b0z8a4lxf.png)
![x=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iytjkob8c453cdntkigo6vyjyk3yzlat9o.png)
Part B) If ∠3=5x-1 and ∠5=3x+11, then the measure of ∠3=?
we know that
∠3=5x-1
The value of x is
![x=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iytjkob8c453cdntkigo6vyjyk3yzlat9o.png)
substitute
∠3=5(6)-1=29°
Part C) If ∠3=5x-1 and ∠5=3x+11, then the measure of ∠1=?
we know that
∠1=∠3 ----> by vertical angles
we have
∠3=29°
therefore
∠1=29°
Part D) If ∠3=5x-1 and ∠5=3x+11, then the measure of ∠2=?
we know that
∠1+∠2=180° ----> by supplementary angles
we have
∠1=29°
substitute
29°+∠2=180°
∠2=180°-29°
∠2=151°