Question

Factor by grouping. 6p2 – 17p – 45

Answer 1

For this case we must factor the following expression:

`6p ^ 2-17p-45`

We must rewrite the term of the medium as two numbers whose product is
`6 * (- 45) = - 270`

And whose sum is -17

These numbers are: -27 and +10:

`6p ^ 2 + (- 27 + 10) p-45\\6p ^ 2-27p + 10p-45`

We group:

`(6p ^ 2-27p) + 10p-45`

We factor the maximum common denominator of each group:

`3p (2p-9) +5 (2p-9)`

We factor
`(2p-9)` and finally we have:

`(2p-9) (3p + 5)`

Answer:

`(2p-9) (3p + 5)`

Answer 2

(2p - 9)(3p + 5)

Explanation:

We have the polynomial: 6p2 – 17p – 45

Rewrite the middle term as a sum of two terms:

6p2 + 27p - 10p - 45

Factor:

3p(2p - 9) + 5(2p - 9)

→ (2p - 9)(3p + 5)