Answer:
- Mean 40.2
- Median 41.5
- Mid-range 38.5
- Mode 48
Step-by-step explanation:
Arrange the given data in increasing order
Given, 33, 48, 41, 29, 40, 48, 44, 42, 49, 28.
⇒28,29,33,40,41,42,44,48,48,49
⇒number of sample ,n, =10
⇒The mean is sum of sample÷number of samples
![28+29+33+40+41+42+44+48+48+49=402\\\\\\\\n=10\\\\mean=(402)/(10) =40.2](https://img.qammunity.org/2020/formulas/physics/middle-school/whlc47e8p133hcayku89n7nm503i83t7xn.png)
⇒Median is the center value in the data set
28,29,33,40,41,42,44,48,48,49---------In this case , median is half sum of 41 and 42
![median=(41+42)/(2) =(83)/(2) =41.5](https://img.qammunity.org/2020/formulas/physics/middle-school/b4hq2z2vl8hj55m8wb49wg8olshme112dd.png)
⇒The mid-range is the mean of the sum of the least and greatest value
=(28+49)÷2 =77÷2=38.5
⇒Mode is the value that appears most in the data set
28,29,33,40,41,42,44,48,48,49-----------mode is 48