Question

A marble is randomly selected from a bag containing 15 black, 12 white, and 6 clear marbles. Find P(not clear). Round

to the nearest percent if necessary.
A.18%
B.82%
C.64%
D.88%

Answer 1

A 18%

Explanation:

I believe it should be A because there is no specific type a marble specified therefore if you do

12/33--> 0.36 times 100= 36 % which isn't an option

15/33->0.45 times 100= 45 % which also isn't an option

6/33= 0.18 times 100= 18% this is the only option given

Answer 2

B. 82%

Explanation:

From the question; A marble is randomly selected from a bag containing 15 black, 12 white, and 6 clear marbles. Find P(not clear).

To find p(not clear), we use this formula;

P(not clear) = 1 - p(clear)

To proceed we first have to find p(clear) and the minus it from 1

But,

probability = Required outcome/ all possible outcome

In the question, since what we are looking for now is probability of clear, so our 'required outcome' is the number of marble which is 6,

all possible outcome is the number of all the marbles; 15 + 12 + 6 = 33

We can now proceed to find the probability of clear marble, hence;

probability = Required outcome/ all possible outcome

p(clear marble) = 6/33

Now, we go ahead to find the probability of 'not clear marble'

P(not clear) = 1 - p(clear)

= 1 - 6/33

= 1 - 0.181818

=0.818182

P(not clear) = 0.818182

But the question says we should round our answer to the nearest percent, so we will multiply our answer by 100%

p(not clear) = 0.818182 × 100%

p(not clear) = 82% to the nearest percent