Answer:
The type of wire
Step-by-step explanation:
The EMF is induced in the closed conducting loop whenever there is a change in the magnetic flux linked with it. Mathematically, it is given by :

Where
is the magnetic flux

For n number of coils,

Where
B is the magnetic field
A is the area of the coil
If the coil is moved with the speed of v in the magnetic field, then induced EMF is given by :

l is the length of the coil
So, the induced EMF depends on the following factors:
- magnetic field
- velocity of the wire
- length of the wire in the field
So, the type of wire do not change the induced emf of the coil. Hence, the correct option is (b).