Answer:
Graph the two points (0,1) and (2,-1) then connect them with a straight edge.
Explanation:
The transformed graph is still a line since the parent is a line.
![g(x)=(-1)/(2)f(x+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ubi7j8slgh426msnselt0tae4vh2cdnb0u.png)
Identify two points that cross nicely on your curve for f:
(2,-2) and (4,2)
So I'm going to replace x in x+2 so that x+2 is 2 and then do it also for when x+2 is 4.
x+2=2 when x=0 since 0+2=2.
x+2=4 when x=2 since 2+2=4.
So plugging in x=0:
![g(x)=(-1)/(2)f(x+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ubi7j8slgh426msnselt0tae4vh2cdnb0u.png)
![g(0)=(-1)/(2)f(0+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4wbexzneln9t49gf1eqsy7iv702e4m9hba.png)
![g(0)=(-1)/(2)f(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/6rhbje2vcldsu6nm4ykrwk2l5y1zbpdf9f.png)
since we had the point (2,-2) on line f.
so g contains the point (0,1).
So plugging in the other value we had for x, x=2:
![g(x)=(-1)/(2)f(x+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ubi7j8slgh426msnselt0tae4vh2cdnb0u.png)
![g(2)=(-1)/(2)f(2+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/w6zdd8uu2ewuzhqlb1rpsny59k8mlqfwfb.png)
![g(2)=(-1)/(2)f(4)](https://img.qammunity.org/2020/formulas/mathematics/high-school/16wms74yn7tddm7oy9zf0lb9c78t2rsxdf.png)
since we had the point (4,2) on the line f.
so g contains the point (2,-1).
Graph the two points (0,1) and (2,-1) then connect them with a straight edge.