Question

How much energy is required to melt 13.00 kg of ice at 273 K? The specific latent heat of fusion of ice is 3.36 x 10^5 J kg-1.

A. 1.19 x 10^9 J

B. 2.58 x 10^4 J

C. 4.37 x 10^6 J

D. 1174.83 J

Answer 1

Answer : The amount of heat required is, (C)
`4.37* 10^6J`

Explanation :

Formula used :

`q=L* m`

where,

q = heat required = ?

L = specific latent heat of fusion of ice =
`3.36* 10^5J/kg`

m = mass of ice = 13.00 kg

Now put all the given values in the above formula, we get:

`q=(3.36* 10^5J/kg)* (13.00kg)`

`q=4.37* 10^6J`

Therefore, the amount of heat required is,
`4.37* 10^6J`

Answer 2

You use the information given by the question about latent heat of fusion of ice and construct the following reasoning:

if you need 3.36 × 10⁵ J to melt 1 kg of ice

then you need X J to melt 13 kg of ice

X = (13 × 3.36 × 10⁵)/1 = 43.68 × 10⁵ J = 4.368 × 10⁶ J ≈ 4.37 × 10⁶ J