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Given point (-6, -3) and a slope of 4, write an equation in point-slope form. a. y - 3 = 4(x - 6) c. y + 3 = 4(x + 6) b. y + 3 = 4(x - 6) d. y - 3 = 4(x + 6) Please select the best answer from the choices provided A B C D

User Naseem
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2 Answers

2 votes


\huge{\boxed{y+3=4(x+6)}}

Point-slope form is
y-y_1=m(x-x_1), where
m is the slope and
(x_1, y_1) is a known point on the line.

Substitute in the values.
y-(-3)=4(x-(-6))

Simplify the negative subtraction.
\boxed{y+3=4(x+6)}

User Careen
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5.1k points
6 votes

For this case we have that by definition, the point-slope equation of a line is given by:


y-y_ {0} = m (x-x_ {0})

We have as data that:


(x_ {0}, y_ {0}): (- 6, -3)\\m = 4

Substituting in the equation we have:


y - (- 3) = 4 (x - (- 6))\\y + 3 = 4 (x + 6)

Finally, the equation is:
y + 3 = 4 (x + 6)

Answer:


y + 3 = 4 (x + 6)

User Eric Clack
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