Question

A company is replacing cables with fiber optic lines in rectangular casing BCDE. If segment DE = 2.5 cm and segment BE = 3 cm, what is the smallest diameter of pipe that will fit the fiber optic line?

Answer 1

3.9

Explanation:

use Pythagorean Theorem

plus i took the test :)

Answer 2

The smaller diameter is
`3.9\ cm`

Explanation:

see the attached figure to better understand the problem

we know that

The diameter of the circle is equal to BD

Applying the Pythagoras Theorem

`BD^(2) =BE^(2) +DE^(2)`

substitute the given values

`BD^(2) =3^(2) +2.5^(2)\\ BD^(2) =15.25\\ BD=3.9\ cm`