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What is the equation that passes through (4, 3) and (2, -1)?

Y = 2x - 5

y = 4x -13

y = 6x+4

y = 1/2 x -2

User Silvestris
by
8.4k points

2 Answers

1 vote

Answer: first option.

Explanation:

The equation of the line in Slope-Intercept form is:


y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

To find "m", we need to substitute the coordinates of the points (4, 3) and (2, -1) into this formula:


m=(y_2-y_1)/(x_2-x_1)

We can identify that:


y_2=-1\\y_1=3\\x_2=2\\x_1=4

Then:


m=(-1-3)/(2-4)\\\\m=2

To find "b" we must substitute the slope and one of the given points into
y=mx+b and solve for "b". Then, this is:


3=2(4)+b\\\\3-8=b\\\\b=-5

Therefore, the equation of this line is:


y=2x-5

User Raviture
by
8.4k points
6 votes

Answer:

y = 2x - 5

Explanation:

We are to find the equation of line the line which passes through the points (4, 3) and (2, -1).

Finding the slope:

Slope =
(3-(-1))/(4-2) =2

Substituting the coordinates of one of the given points and slope in the standard form of an equation to find the y intercept.


y=mx+c


-1 = 2 (2) + c \\\\ c = - 5

So the equation of the line would be
y=2x-5

User Fahmy
by
8.7k points

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