Question

Let f(x) = 9x3+ 21x2^ - 14 and g(x) = 3x + 1. Find "
f (x) over g (x)​

Answer 1

on the flvs test it is option A

Explanation:

Answer 2

`(f(x))/(g(x))=3x^2+6x-2-(12)/(3x+1)`

Explanation:

The first function is
`f(x)=9x^3+21x^2-14`

The second function is
`g(x)=3x+1`.

`(f(x))/(g(x))=(9x^3+21x^2-14)/(3x+1)`

We perform the long division as shown in the attachment to obtain the quotient as:
`Q(x)=3x^2+6x-2` and remainder
`R=-12`.

Therefore:

`(f(x))/(g(x))=3x^2+6x-2-(12)/(3x+1)`

where
`x\\e -(1)/(3)`