Answer:
Part 1) The actual length of the banner is
![1.2\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3vhpwlgk9e59loqqdohslnl9aeeztzz0zy.png)
Part 2) The area of the banner is
![3.24\ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6qo58ms59y73d137z1lxtrg0i3t7vrj9f6.png)
Explanation:
we know that
The scale of the drawing is
![(1)/(30)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pvi599y45nj6q3aqsq0zqwll38rrs3uqwp.png)
That means ----> 1 cm on the drawing represent 30 cm in the actual
Using proportion
Find out the actual dimensions of the banner
Let
L the actual length of the banner
W the actual width of the banner
For a length of 4 cm in the drawing
![(1)/(30)=(4)/(L)\\ \\ L=30*4\\ \\L=120\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2s4sg6dlzbz2wlyhdj1wgm60ipbth5olnb.png)
Convert the actual length to meters
![L=120/100=1.2\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/eekcdfd6se2gn9qqwqk6j4o2k4s2bnfh8i.png)
For a width of 9 cm in the drawing
![(1)/(30)=(9)/(W)\\ \\ W=30*9\\ \\W=270\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wthny8htk9nkivhmkyow8hkfq1janoreyi.png)
Convert the actual width to meters
![W=270/100=2.7\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qdpdjw3j9sangyylxf4v4fq2q3ncp7u6dg.png)
Find the area of the banner
![A=1.2*2.7=3.24\ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/62fqaabamsx54ir4vpq7igvur35ziboeb8.png)