Question

In a hospital ward, there are 15 nurses and 3 doctors. 9 of the nurses and 1 of the doctors are female. If a person is randomly selected from this group, what is the probability that the person is male or a doctor?

nine over eighteen
two over fifteen
eight over fifteen
eight over eighteen

Answer 1

`\large\boxed{\text{Nine over eighteen}}`

Explanation:

In this question, we're trying to find the probability of picking a person that is a male or a doctor.

We know that there are:

• 15 nurses
• 3 doctors
• 9 of the nurses are female
• 1 doctor is a female

With the information above, we can find the probability.

Lets first find how many male nurses there are. To find this, we would get our total amount of nurses (15) and subtract it by 9, due to the fact that 9 of the nurses are female.

`15-9=6`

This means that there are 6 male nurses.

6 would be added to our probability.

We're not done yet, we also need to add the chance of getting a doctor in our probability.

Since there's 3 doctors, we would just add 3 to our probability.

`6+3=9`

Now, we need to find the total. When we add all together, we would get 18. This means that 18 would go on our denominator and 9 will go on our numerator.

This means that the chance of getting a male or a doctor would be
`(9)/(18)`, or nine over eighteen.

I hope this helped you out.

Good luck on your academics.

Have a fantastic day!