Question

What is the equation of a line which includes points (-5, 5) and (2, 5)?

Answer 1

Hello!

The answer is:

The equation of the line which includes the points (-5,5) and (2,5) is:

`y=5`

Why?

To find the line which includes the points (-5,5) and (2,5) we can use the following equation:

`y-y_1=(y_2-y_1)/(x_2-x_1)*(x-x_1)`

So, using the points (-5,5) and (2,5), we have:

`y-5=(5-5)/(2-(-5))*(x-(-5))`

`y-5=(0)/(2+5)*(x-(-5))`

`y-5=0*(x+5)`

`y-5=0`

`y=5`

We have that the equation of the line which includes the points (-5,5) and (2,5) is:

`y=5`

Have a nice day!

Note: I have attached a picture for better understanding.