Answer: 0.33
Explanation:
Let,
- E1 be the coin which has heads in both faces
- E2 be the coin which has tails in both faces
- E3 be the coin which has a head in one face and a tail in the other.
In this question we are using the Bayes' theorem,
where,
P(E1) = P(E2) = P(E3) =
As there is an equal probability assign for choosing a coin.
Given that,
it comes up heads
so, let A be the event that heads occurs
then,
P(A/E1) = 1
P(A/E2) = 0
P(A/E3) =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ybjkeso7qr5r7js5h0mv9de35dih0sxfpl.png)
Now, we have to calculate the probability that the opposite side of coin is tails.
that is,
P(E3/A) = ?
∴ P(E3/A) =
![(P(E3)P(A/E3))/(P(E1)P(A/E1) + P(E2)P(A/E2) + P(E3)P(A/E3) )](https://img.qammunity.org/2020/formulas/mathematics/college/lkrmtlp3t0731za2nv0fqgikk8om3zz0bu.png)
=
![((1/3)(1/2))/((1/3)(1) + 0 + (1/2)(1/3))](https://img.qammunity.org/2020/formulas/mathematics/college/d9bkqcptp5f1qkjg201j0cwvdmfqbxs3qy.png)
=
×
![(6)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/38gelfriuawvybxmeumeklbef86gdwp1rx.png)
=
![(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o08xg954t1gbzo9avralvfomcybk63rm02.png)
= 0.3333 ⇒ probability that the opposite face is tails.