Question

The temperature of a system drops by 45°F during a cooling process. Express this drop in temperature in K, R, and °C

Answer 1

280.3722 K,504.67°R ,7.222°C

Step-by-step explanation:

FAHRENHEIT TO KELVIN: T(K)=(T(F°)+459.67)
`(5)/(9)`

we have to convert 45°F=(45+459.67)×
`(5)/(9)`

=280.3722

FAHRENHEIT TO RANKINE :T(R°)=T(F°)+459.67

we have to convert 45°F=45+459.67

=504.67

FAHRENHEIT TO CELSIUS:T(C°)=
`(F-32)/(9)`×5

we have to convert 45°F=
`(45-32)/(9)`×5

=7.22°C