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The specific gravity of a fluid with a weight density of 31.2 lb/ft is a. 2.00 b. 0.969 c. 0.500 d. 1.03
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The specific gravity of a fluid with a weight density of 31.2 lb/ft is a. 2.00 b. 0.969 c. 0.500 d. 1.03

User Chef
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Answer:

Answer is c 0.500

Step-by-step explanation:


SpecificGravity=(\rho _(fluid)*g)/(\rho _(water)*g)

We know that
\rho_(water)=62.42lb/ft^(3)

Applying values we get


SpecificGravity=(31.2)/(62.4)=0.5

User Virtuozzo
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