Answer:
0.4
Explanation:
Given
60 % wear neither ring nor a necklace
20 % wear a ring
30 % wear necklace
This question can be Solved by using Venn diagram
If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is
![P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1](https://img.qammunity.org/2020/formulas/mathematics/college/bszi6n1qorwpati4obhvp6jgzycvkqnupj.png)
![P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4](https://img.qammunity.org/2020/formulas/mathematics/college/zft6lkvfrs8bm7vx4sn3hh27s1mq4a07cp.png)
The sum of probabilty is equal to 1 because it completes the set
Therefore the required probabilty is 0.4