Answer:
Part a)
Q = 3198 J
Part b)
It is compression of gas so this is energy transferred to the gas
Step-by-step explanation:
Part a)
Energy transfer during compression of gas is same as the work done on the gas
In isothermal process work done is given by the equation
![W = nRT ln((V_2)/(V_1))](https://img.qammunity.org/2020/formulas/physics/college/zttx02yf6ej14782tyyb8ghxo5wog6mcrw.png)
now we know that
n = 1.4 moles
T = 27 degree C = 300 K
![V_2 = 2.5 m^3](https://img.qammunity.org/2020/formulas/physics/college/ks9myt55h1m8hi2ahk3y7nrfuvrxiixoii.png)
![V_1 = 1 m^3](https://img.qammunity.org/2020/formulas/physics/college/gnnlbu75y76ydknvvvh9ad68icjkeostpt.png)
now we have
![W = (1.4)(8.31)(300)(ln(2.5)/(1))](https://img.qammunity.org/2020/formulas/physics/college/h7hbyzlld1e6v9u4ztce6bgxsjrolf4psx.png)
![Q = 3198 J](https://img.qammunity.org/2020/formulas/physics/college/j2ot1hin8pkpje6f9krg8oks9n475smzl0.png)
Part b)
It is compression of gas so this is energy transferred to the gas