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Please help I'm about to fail this class

If you only know one or two, just please help with what you can. Its fine if you can't do all three. <3
If you want more points afterwards, I can give you more. Just please lol

Show your work!! Its really important!
Using the quadratic formula, solve the equations, stating the discrimination and amount of real solution(s) (0, 1, or 2)

-3t^2+12t=2

3x^2+6x+1=2

3x^2+6x-4=0

1 Answer

6 votes

Answer:

{ \left(-3t \right) }^{ 2 } +12t = { \left(2 \cdot 3x \right) }^{ 2 } +6x+1 = { \left(2 \cdot 3x \right) }^{ 2 } +6x-4 = 0

Explanation:

User M P Mathugama
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