Question

Lithium at 20°C is BCC and has a lattice constant of 0.35092 nm. Calculate a value for the atomic radius of a lithium atom in nanometers.

Answer 1

the atomic radius of a lithium atom is 0.152 nm

Step-by-step explanation:

Given data in question

structure = BCC

lattice constant (a) = 0.35092 nm

to find out

atomic radius of a lithium atom

solution

we know structure is BCC

for BCC radius formula is
`√(3)` /4 × a

here we have known a value so we put a in radius formula

radius =
`√(3)` /4 × a

radius =
`√(3)` /4 × 0.35092

radius = 0.152 nm

so the atomic radius of a lithium atom is 0.152 nm