Question

A student plans to prepare 3.0 liters of 0.50 m naoh solution from a 6.0 m naoh stock solution, how many millilters of stock solution should the student use

Answer 1

Answer : The volume of NaOH stock solution used should be, 250 ml

Solution :

According to the neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of NaOH solution = 0.50 M

`V_1` = volume of NaOH solution = 3.0 L

`M_2` = molarity of NaOH stock solution = 6.0 M

`V_2` = volume of NaOH stock solution = ?

Now put all the given values in the above law, we get the volume of NaOH stock solution.

`(0.50M)* (3.0L)=(6.0M)* V_2`

`V_2=0.25L=250ml` (1 L = 1000 ml)

Therefore, the volume of NaOH stock solution used should be, 250 ml