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Prove that if BA=I then BA=AB.

User IanPudney
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1 Answer

3 votes

Answer with Step-by-step explanation:

Since we have given that


BA=I

As we know that

AA⁻¹ = I (A is invertible matrix)

Multiplying A⁻¹ on the both the sides:


BAA^(-1)=IA^(-1)\\\\B=A^(-1)

Using the above result, we get that


BA=I=AA^(-1)\\\\BA=AB

Therefore, BA = AB

Hence, proved.

User Amr Rady
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