Question

One integer is 1/3 times another. The sum of their squares is 90. What are the two integer?

Answer 1

Hence, the two integers could be:

3 and 9

0R

-3 and -9

Explanation:

Let the two integers be denoted by a and b.

It is given that:

One integer is 1/3 times another.

i.e. let

`a=(1)/(3)b`

i.e.

`b=3a`

Also,

The sum of their squares is 90.

i.e.

`a^2+b^2=90\\\\i.e.\\\\a^2+(3a)^2=90\\\\i.e.\\\\a^2+9a^2=90\\\\i.e.\\\\10a^2=90\\\\i.e.\\\\a^2=9\\\\i.e.\\\\a=\pm 3`

Hence, when a=3 we have:

`b=9`

and when,

`a=-3`

then b=-9