Question

Math help ASAP!!!!!!!!!!

Answer 1

`(r + s)(x)=4x+3`

`(r * s)(x)=3x^2+x-4`

`(r - s)(-1)=-3`

Explanation:

We know that:

`r(x) =x-1\\s(x)=3x+4`

To find
`(r + s) (x)` we add the function
`r (x)` with the function
`s (x)`

So

`(r + s)(x)=r(x)+s(x)`

`(r + s)(x)=x-1 + 3x+4`

`(r + s)(x)=4x+3`

To find
`(r * s) (x)` we multiply the function
`r (x)` with the function
`s (x)`

So

`(r *s)(x)=r(x)*s(x)`

`(r * s)(x)=(x-1)(3x+4)`

Using the distributive property we have left that

`(r * s)(x)=3x^2+4x-3x-4`

`(r * s)(x)=3x^2+x-4`

To find
`(r - s) (-1)` we subtract the function
`r (x)` with the function
`s (x)` and then evaluate in (-1)

Then:

`(r - s)(-1)=r(x)-s(x)`

`(r - s)(-1)=x-1 - (3x+4)`

`(r - s)(-1)=x-1-3x-4`

`(r - s)(-1)=-2x-5`

`(r - s)(-1)=-2(-1)-5`

`(r - s)(-1)=2-5`

`(r - s)(-1)=-3`

Answer 2

(r+s) (x) = 4x+3

(r*s) (x) = 3x^2 +x-4

(r-s) (-1) = -3

Explanation:

r(x) = x-1

s(x) = 3x+4

(r+s) (x) = x-1 + 3x+4

Combine like terms

= 4x+3

(r*s) (x) = ( x-1) ( 3x+4)

FOIL

= 3x^2 +4x-3x-4

= 3x^2 +x-4

(r-s) (x) = x-1 - (3x+4)

Distribute the minus sign

=x-1-3x-4

=-2x-5

Let x = -1

(r-s) (-1) = -2(-1) -5

2-5

-3