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How long does it take light to travel across the width of a Pb nucleus of radius 7.1 fm?

User Jeppe
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Answer:

The light takes 4.73×10⁻²³ s to travel across the width of the Pb nucleus.

Step-by-step explanation:

Given :

Radius of Pb nucleus = 7.1 fm

Also, The conversion of fm into m is shown below:

1 fm = 10⁻¹⁵ m

The radius of Pb nucleus = 7.1×10⁻¹⁵ m

The width of Pb nucleus (diameter) = 2× Radius of the nucleus

Thus,

Width of Pb nucleus = 2×7.1×10⁻¹⁵ m = 14.2×10⁻¹⁵ m

The Speed of light = 3×10⁸ m/s

The formula for Speed is shown below:


Speed=(Distance)/(Time)

Time can be calculated from the above formula as:


Time=(Distance)/(Speed)

Applying values in the above formula as:


Time=(14.2* 10^(-15) m)/(3* 10^(8) m/s)

Time = 4.73×10⁻²³ s

User Cababunga
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