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Find all the zeros of the polynomial function f(x) = x + 2x² - 9x - 18 a) (-3) b) (-3. -2,3) c) (-2) d) (-3.2.3) e) none

User Fung
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1 Answer

6 votes

Answer:x=-3,-2,3

Explanation:

Given equation of polynomial is


x^(3)+2x^2-9x-18=0

taking
x^3 and -9x together and remaining together we get


x^3-9x+2x^2-18=0


x\left ( x^2-9\right )+2\left ( x^2-9\right )


x\left ( \left ( x+3\right )\left ( x-3\right )\right )+2\left ( \left ( x+3\right )\left ( x-3\right )\right )


taking \left ( x+3\right )\left ( x-3\right ) as common


\left ( x+2\right )\left ( x+3\right )\left ( x-3\right )=0

therefore

x=-3,-2,3

User Eaque
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