Question

Determine the total energy E of water vapor with a mass of 2.50 kg, a specific internal energy μ= 2780 kJ/kg, traveling at a velocity of 56.0 m/s at a height of 3.50 m. First draw a sketch of your system

Answer 1

Total energy E of water vapor is 6954005.8 J

Step-by-step explanation:

given data:

mass = 2.50 kg

specific internal energy μ = 2780 kJ/kg = 2780 ×10³ J/kg

velocity of water vapor = 56 m/s

height h or z = 3.50 m

we know that total energy is given as

total energy E = mμ +
`(1)/(2)`mv² + mgh

= m(μ +
`(1)/(2)`v² +gh)

= 2.5(2780 ×10³ +
`(1)/(2)`×56²+9.81×3.50)

E = 6954005.8 J