Question

Determine the theoretical density of a fictitious BCC metal with a gram molecular weight of 148.09 grams per mole and atomic radius of 1.918 angstroms. Express result in grams per cubic centimeter. Enter numerical values only. Do not enter units. Do not enter signs.

Answer 1

theoretical density = 5.69 gm/cm^3

Step-by-step explanation:

theoretical density is given as =
`(atomic weight *n*10^(-6))/(N_a*a^(3))`

where

`a = (4r)/(√(3))`

`a = (4*1.918*10^(-10))/(√(3))`

`a = 4.42 *10^(-10)`

N_a = 6.023 *10^{23}

for BCC n = 2

atomic weight = 148.09

so theoretical density is =
`(148.06 *2*10^(-6))/(6.023 *10^(23)*[4.42 *10^(-10)]^(3))`

theoretical density = 5.69 gm/cm^3