Question

Cesium exists at room temperature as a body centered cubic structure with lattice paramater a=6.06 A. What is the density of cesium?

Answer 1

`\rho=1.98 (g)/(cm^3)`

Step-by-step explanation:

Molecular mass of Cesium M=132.9 g/mol

To find density

`\rho=(Z* M)/(a^3N_a)`

Where
`N_a=6.022* 10^(23)`

a is the lattice parameter,Z=2 for body centered.

`\rho=(2* 132.9)/((6.06* 10^(-8))^3* 6.022* 10^(23))`

So
`\rho=1.98 (g)/(cm^3)`