Answer:
96.1%
Step-by-step explanation:
We know that lift force
![F_L=(1)/(2)C_L\rho AV^2](https://img.qammunity.org/2020/formulas/engineering/college/5kbiubpixm7n8hy839v3ihkxzz0v86jlls.png)
------------(1)
Where
is the lift force coefficient .
ρ is the density of fluid.
A is the area.
V is the velocity.
Now when speed is increased by 2 % and all other parameter remains constant except
.
Let;s take new value of lift force coefficient is
.
![F_L=(1)/(2)C_L'\rho A(1.02V)^2](https://img.qammunity.org/2020/formulas/engineering/college/nfqlrj5as8gt35xczmq9md4794s8f1v913.png)
-----------(2)
Now from equation 1 and 2
⇒
![C_L'=0.961C_L](https://img.qammunity.org/2020/formulas/engineering/college/aw2190fuvunbd3u3jxceo2bw6g2j0hwqhe.png)
So we can say that revised value of lift force coefficient is 96.1% of original value.