Question

An indirect contact heat exchanger operating at steady state contains a shell with a single tube through it. The fluid flowing through the tube enters at 1kg/s with and enthalpy of 100kJ/kg. It exits with an enthalpy of 500kJ/kg. The fluid flowing through the shell enters with a mass flow rate of 4kg/s and an enthalpy of 1000kJ/kg. Determine the enthalpy at the exit of the shell.

Answer 1

Answer:900 KJ/kg

Step-by-step explanation:

Given data

mass flow rate of fluid through tube is=1 kg/s

Initial enthalpy of fluid through tube=100 KJ/kg

Final enthalpy of fluid through tube=500KJ/kg

mass flow rate of fluid through shell is=4 kg/s

Initial enthalpy of fluid through shell=1000 KJ/kg

Final enthalpy of fluid through shell=
`h_2`

since heat lost by Shell fluid is equal to heat gain by Tube fluid

heat lost by Shell fluid=
`4* c\left ( 1000-h_2\right )`

Heat gain by tube Fluid=
`1* c\left ( 500-100\right )`

Equating both heats

`4* c`
`\left ( 1000-h_2\right )`=
`1* c\left ( 500-100\right )`

`h_2`=900 KJ/kg