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A strong electromagnet produces a uniform magnetic field of 1.60 T over a cross-sectional area of 0.340 m2. A coil having 190 turns and a total resistance of 16.0 Ω is placed around the electromagnet. The current in the electromagnet is then smoothly reduced until it reaches zero in 20.0 ms. What is the current induced in the coil?

User Tuxxi
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1 Answer

2 votes

Answer:

i = 323 A

Step-by-step explanation:

Initial flux due to magnetic field from the coil is given as


\phi = NB.A

here we will have


N = 190


B = 1.60 T


A = 0.340 m^2

now the flux is given as


\phi_1 = (190)(1.60)(0.340) = 103.36 T m^2

finally current in the electromagnet changed to zero

so final flux in the coil is zero


\phi_2 = 0

now we know that rate of change in flux will induce EMF in the coil

so we will have


EMF = (\phi_1 - \phi_2)/(\Delta t)


EMF = (103.36 - 0)/(20 * 10^(-3))


EMF = 5168 Volts

now induced current is given as


i = (EMF)/(R)


i = (5168)/(16) = 323 A

User Lujop
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