Answer:
The difference of head in the level of reservoir is 0.23 m.
Step-by-step explanation:
For pipe 1

For pipe 2

Q=2.8 l/s
![Q=2.8* 10^{-3]](https://img.qammunity.org/2020/formulas/engineering/college/iku802x1ehgym8s5bbnz5rlt9d8ei21x9z.png)
We know that Q=AV




head loss (h)

Now putting the all values

So h=0.23 m
So the difference of head in the level of reservoir is 0.23 m.