Question

A snowboarder is at the top of a 90 foot tall slope making an angle of 40 degrees with the horizontal direction. If the snowboarder weighs 170 pounds and the coefficient of friction between the snow and snowboarder is 0.2, what is the snowboarders acceleration down the hill?

Answer 1

Answer:
`4.802 m/s^2`

Step-by-step explanation:

height of slope(h) =90 foot

`\theta =40`

weight of snowboarder=170 pounds\approx 77.1107 kg

`\mu =0.2`

as the snowboarder is sliding down the slope therefore

Now net acceleration of snowboarder is

`a_(net)=gsin\theta -\mu \cdot gcos\theta`

`a_(net )=9.81* sin\left ( 40\right )-0.2* 9.81* cos\left ( 40\right )`

`a_(net )=4.802 m/s^2`