Question

A Carnot machine operates with 25% efficiency, whose heat rejection reservoir temperature is 300K. Determine the temperature at which the machine absorbs heat.

Answer 1

The temperature at which observed heat is 400 K

Step-by-step explanation:

Given data:

rejection reservoir temperature at exit
`T_(L)` is 300 k

the efficiency of a engine is η = 25%

we know that efficiency of Carnot is given as

`\eta = (1-(T_(L))/(T_(H)))*100`

Putting all value to obtained temperature at which observed heat

`0.25 = (1-(300)/(T_(H)))`

`T_(H)` = 400 K